Data Modeling and Databases Lab 3: Introduction to SQL
Basic SQL query structure
Data manipulation
Inserting
Updating
Deleting
Expressions
Tables
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
Exercise
QA?

Data Modeling and Databases Lab 3: Introduction to SQL

1. Data Modeling and Databases Lab 3: Introduction to SQL

Bulat Gabbasov, Albina Sayfeeva
Innopolis University
2016

2. Basic SQL query structure

• Basic SQL query structure consists of SELECT, FROM, WHERE, GROUP BY and ORDER BY clauses.
• SELECT [ALL | DISTINCT] expressions
• specifies the columns to appear in the result
• distinct keyword can be used to eliminate duplicates
• FROM from_items
• specifies the relations to be used
• WHERE condition
• filters the tuples
• GROUP BY expression
• groups rows with the same column values
• the HAVING construct can be used to further filter the groups
• ORDER BY expression
• defines the order of the resulting tuples
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3. Data manipulation

• INSERT
• Inserts a tuple into the specified table
• INSERT INTO tablename (list of columns)
VALUES (list of values), ...
• UPDATE
• Updates all tuples that match specified condition
• UPDATE tablename SET column = newvalue, ...
WHERE condition
• DELETE
• Deletes all tuples that match specified condition
• DELETE FROM tablename WHERE condition
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4. Inserting

• Create a new student Harvey Specter:
INSERT INTO students
(student_id, firstname, lastname) VALUES
(1, 'Harvey', 'Specter')
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5. Updating

Change firstname of all students having student_id = 1 to ‘John’:
UPDATE students
SET firstname = 'John'
WHERE student_id = 1
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6. Deleting

• Delete student having student_id = 1 from table students:
DELETE FROM students WHERE student_id = 1
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7. Expressions

• Calculate expression 1 + 1 and name it as two:
SELECT 1 + 1 AS two
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8. Tables

• Return list of all students:
SELECT * FROM students
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9. Exercise

• Insert a new department named ‘Machine Learning’ and leaded with professor identified by professor_id = 1
INSERT INTO departments
VALUES (4, 'Machine Learning', 1)
• Change name of the newly created department to ’Advanced Machine Learning’
UPDATE departments
SET name = 'Advanced Machine Learning'
WHERE name = 'Machine Learning’
• Delete new newly created department
DELETE FROM departments
WHERE name = 'Advanced Machine Learning'
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10. Exercise

• Find the address of the student with first name "Donna”
SELECT address FROM students
WHERE firstname = 'Donna'
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11. Exercise

• Find all students who are either male or are from Kazan
SELECT * FROM students
WHERE gender = 'm' or address = 'Kazan'
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12. Exercise

• Find all courses that worth at least 9 credits and are given by MSIT
department
• Hint: department_id for MSIT-SE is 1.
SELECT * FROM courses
WHERE credits >= 9 AND department_id = 1
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13. Exercise

• Find names and salaries of professors who earn less than 15 000
SELECT firstname, lastname, salary
FROM professors WHERE salary < 15000
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14. Exercise

• Find students born earlier than 1980
SELECT * FROM students
WHERE birthdate < '1980-01-01'
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15. Exercise

• List full names of all students living in Moscow
• Hint: concatenation operator a || b
SELECT
firstname || ‘ ‘ || lastname AS fullname
, address
FROM Students WHERE address = ‘Moscow’
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16. Exercise

• Find students who's address contains "k" letter
SELECT * FROM students WHERE address LIKE '%k%'
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17. Exercise

• Find students who's lastname consists of 7 letters and ends with "n”
SELECT * FROM students
WHERE lastname LIKE '______n'
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18. Exercise

• Order and display students by lastname (alphabetically)
SELECT * FROM students
ORDER BY lastname
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19. Exercise

• Order and display students by lastname and then by firstname
(alphabetically)
SELECT * FROM students
ORDER BY lastname, firstname
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20. Exercise

• Order by login : first letter of firstname + full lastname in descending order
• Hint: use SUBSTRING(column from begin for length)
SELECT SUBSTRING(firstname from 1 for 1)
|| lastname AS login, *
FROM students
ORDER BY 1 DESC
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21. Exercise

• Find names of male students who got more than 50 for any course
SELECT s.firstname, s.lastname
FROM students s
WHERE gender = 'm' AND
EXISTS(SELECT 1 FROM enrollment e
WHERE e.student_id = s.student_id
AND e.grade > 50)
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22. Exercise

• Which students are enrolled in DMD course?
SELECT s.* FROM students s
NATURAL JOIN enrollment e
NATURAL JOIN courses c
WHERE c.name = 'DMD'
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23. QA?

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